Which of the following statements is correct for $[Mn(CN)_{6}]^{3-}$ according to valence bond theory?
Updated On: Jul 7, 2022
$d^{2}sp^{3}$, inner orbital complex, paramagnetic, $2.87 \,B.M$
$d^{2} sp^{3}$, inner orbital complex, diamagnetic, zero magnetic moment
$d^{2} sp^{3}$, outer orbital complex, paramagnetic, $3.87 \,B.M$
$dsp^{2}$, outer orbital complex, diamagnetic, zero magnetic moment
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The Correct Option isA
Solution and Explanation
In $[Mn(CN)_{6}]^{3-}$, oxidation state of $Mn = +3, Mn^{3+} = 3d^{4}$$[Mn(CN)_{6}]^{3-}$ :
It has two unpaired electrons.
$\mu=\sqrt{n\left(n+2\right)}=\sqrt{2\left(2+2\right)}=\sqrt{8}$$=2.87 \, B.M.$
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.
