Question:

Which of the following statements is correct?

Updated On: Aug 1, 2022
  • Zeolites have a more closed structure than feldspar.
  • $H _{4} As _{2} O _{7}$ is an 'ortho' acid.
  • Pseudo-alum does not have $Na ^{+}$and $K ^{+}$.
  • Superphosphate of lime is $4 Ca \left( H _{2} PO _{4}\right)_{2}$.
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The Correct Option is C

Solution and Explanation

Pseudo-alum constitute a class in which monovalent atom of true alum is replaced by a divalent atom. Hence, $Na ^{+}$and $K ^{+}$are not present in pseudo-alums. Further feldspar has a more closed structure, $H _{4} As _{2} O _{7}$ is a 'pyro' acid and superphosphate of lime is $Ca \left( H _{2} PO _{4}\right)_{2}+2 CaSO _{4}$.
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Top Questions on GROUP 1 ELEMENTS

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Concepts Used:

Group 1 Elements

Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkali metals are characterized by one s-electron in the valence shell of their atoms.

Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:

  • Lithium(Li)
  • Sodium(Na)
  • Potassium (K)
  • Rubidium (Ru)
  • Cesium (Cs)
  • Francium (Fr)

They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.

Electronic Configuration:

  • Alkali metals have one electron in their valence shell.
  • The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
  • They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).

This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.