Question

Which of the following statements about halogens are correct?

• A. HF is the strongest hydrohalic acid
• B. F\(_2\) is the strongest reducing agent among all types of halogen
• C. The order of -ve electron gain enthalpy for halogens is F > Cl > Br > I
• D. F\(_2\) has lower bond dissociation energy than Cl\(_2\)

Hint:

Fluorine is the strongest oxidizing agent, but it has a lower bond dissociation energy than chlorine due to the small size of the molecule and increased electron-electron repulsion.

Answer 1

The Correct Option is D

Let's evaluate each option: - (a) HF is the strongest hydrohalic acid: This statement is correct, HF is a stronger acid than other hydrohalic acids due to the high electronegativity of fluorine. - (b) F\(_2\) is the strongest reducing agent among all types of halogen: This is incorrect, as fluorine is the strongest oxidizing agent, not a reducing agent. - (c) The order of -ve electron gain enthalpy for halogens is F > Cl > Br > I: This is incorrect because the electron gain enthalpy decreases down the group due to increasing atomic size.
So, I > Br > Cl > F. - (d) F\(_2\) has lower bond dissociation energy than Cl\(_2\): This is correct.
Fluorine has a lower bond dissociation energy compared to chlorine because the bond in F\(_2\) is weaker due to electron-electron repulsion in the small fluorine molecule.
Thus, the correct answer is (d).