The question involves understanding the dynamics of an LC circuit, which is a fundamental topic in electromagnetism and electronics. Here, we need to verify which statements are true based on given values of inductance \(L\) and capacitance \(C\).
Given: \(L = 25 \, \text{mH} = 25 \times 10^{-3} \, \text{H}\) and \(C = 4 \, \mu\text{F} = 4 \times 10^{-6} \, \text{F}\)
The resonance frequency (\(f_0\)) of an LC circuit is given by the formula:
\(f_0 = \frac{1}{2\pi \sqrt{LC}}\)
Substituting the given values:
\(f_0 = \frac{1}{2\pi \sqrt{(25 \times 10^{-3})(4 \times 10^{-6})}}\)
Calculating the denominator inside the square root:
\(\sqrt{(25 \times 10^{-3})(4 \times 10^{-6})} = \sqrt{1 \times 10^{-7}} = 1 \times 10^{-3.5}\)
So the resonance frequency is:
\(f_0 \approx \frac{1}{2\pi \times 10^{-3.5}} \approx 503 \, \text{Hz}\)
This confirms that the statement "Resonance frequency is close to 503 Hz" is true.
The impedance (\(Z\)) of an LC circuit at a particular frequency (\(f\)) is given by:
\(Z = \sqrt{(X_L - X_C)^2}\)
Where \(X_L = 2\pi fL\) and \(X_C = \frac{1}{2\pi fC}\).
For \(f = 1000 \, \text{Hz}\):
The calculated impedance is 117 Ω, not 15 Ω. Therefore, the statement "The impedance at 1 kHz is 15 Ω" is false.
To determine whether the voltage leads or lags, we examine the relative sizes of \(X_L\) and \(X_C\):
For \(f = 200 \, \text{Hz}\):
Since \(X_L < X_C\), the voltage lags the current. Therefore, the statement "At a frequency of 200 Hz, the voltage lags the current in the circuit" is true.
For \(f = 700 \, \text{Hz}\):
Since \(X_L > X_C\), the voltage leads the current. Therefore, the statement "At a frequency of 700 Hz, the voltage lags the current in the circuit" is false.
The true statements are:
(i) Study the diagram and name the parts marked as A, B, C, and D.
(ii) Write the function of A and C.
