Which of the following statement is correct for the stability of ions of ethyl alcohol and phenol:
Delocalisation of \(\pi\)-electrons in phenoxide ion
- Delocalisation of electrons in ethoxide ion
- Inductive effect of ethyl and phenyl group
Localisation of \(\pi\)-electrons in phenoxide ion
The Correct Option is A
Solution and Explanation
In phenol, the presence of a benzene ring with its pi electrons allows for delocalization of the lone pair of electrons on the oxygen atom. This delocalization or resonance stabilization makes the phenoxide ion more stable.
In contrast, the ethoxide ion does not have the same level of delocalization as in the phenoxide ion. While it has inductive effects from the ethyl group, it does not exhibit the same extent of resonance stabilization through pi-electron delocalization as seen in phenol.
So, the correct option is (A): Delocalisation of \(\pi\)-electrons in phenoxide ion
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Concepts Used:
Alcohols, Phenols, and Ethers
Alcohol is formed when a saturated carbon atom bonds to a hydroxyl (-OH) group. It is an organic compound that contains a hydroxyl functional group attached to a carbon atom.
Phenol is formed when the -OH group replaces the hydrogen atom in benzene. It is an organic compound in which a hydroxyl group directly attaches to an aromatic hydrocarbon.
Ether is formed when oxygen atom bonds to two alkyl or aryl groups. It is an organic compound that has an oxygen atom that is connected to two aryl and alkyl groups.
Read More: Alcohol, Phenol, and Ethers