Question:
Which of the following sets are correctly matched?
(i) B2H6- electron deficient hydride
(ii) NH3- electron precise hydride
(iii) H2O- electron rich hydride
Which of the following sets are correctly matched?
(i) B2H6- electron deficient hydride
(ii) NH3- electron precise hydride
(iii) H2O- electron rich hydride
(i) B2H6- electron deficient hydride
(ii) NH3- electron precise hydride
(iii) H2O- electron rich hydride
Show Hint
Hydrides are classified based on valence electrons: electron-deficient, electron-precise, and electron-rich.
Updated On: May 26, 2025
- \( i, iii \) only
- \( i, ii, iii \)
- \( ii, iii \) only
- \( i, ii \) only
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The Correct Option is A
Solution and Explanation
Step 1: Classification of Hydrides
- Electron-deficient hydrides: \( B_2H_6 \) (Diborane) lacks enough electrons for bonding, making it electron-deficient.
- Electron-precise hydrides: \( NH_3 \) is not electron-precise because it has a lone pair.
- Electron-rich hydrides: \( H_2O \) has lone pairs and is electron-rich.
Thus, the correct matches are \( B_2H_6 \) and \( H_2O \).
- Electron-deficient hydrides: \( B_2H_6 \) (Diborane) lacks enough electrons for bonding, making it electron-deficient.
- Electron-precise hydrides: \( NH_3 \) is not electron-precise because it has a lone pair.
- Electron-rich hydrides: \( H_2O \) has lone pairs and is electron-rich.
Thus, the correct matches are \( B_2H_6 \) and \( H_2O \).
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