Question

Which of the following sets are correctly matched?
(i) B2H6- electron deficient hydride
(ii) NH3- electron precise hydride
(iii) H2O- electron rich hydride

• A. $i, iii$ only
• B. $i, ii, iii$
• C. $ii, iii$ only
• D. $i, ii$ only

Hint:

Hydrides are classified based on valence electrons: electron-deficient, electron-precise, and electron-rich.

Answer 1

The Correct Option is A

Step 1: Classification of Hydrides
- Electron-deficient hydrides: $B_2H_6$ (Diborane) lacks enough electrons for bonding, making it electron-deficient.
- Electron-precise hydrides: $NH_3$ is not electron-precise because it has a lone pair.
- Electron-rich hydrides: $H_2O$ has lone pairs and is electron-rich.

Thus, the correct matches are $B_2H_6$ and $H_2O$.