Each quantum number must follow these rules:
- Principal quantum number \( n \): any positive integer (here \( n = 2 \), valid)
- Azimuthal quantum number \( l \): \( 0 \leq l < n \)
- Magnetic quantum number \( m_l \): ranges from \( -l \) to \( +l \) in integers
- Spin quantum number \( m_s \): \( +\frac{1}{2} \) or \( -\frac{1}{2} \)
For Option (2):
Given \( l = 0 \), then \( m_l \) must be only 0, not \( \pm 1 \).
So having \( m_l = \pm 1 \) with \( l = 0 \) is not valid.
Hence, this set of quantum numbers is incorrect.
The correct option is (B): \(n=2,l=0,m_l=\pm1,m_s=\pm\frac{1}{2}\)
Given below are two statements: 
Given below are two statements: 
In light of the above statements, choose the correct answer from the options given below:
The product (P) formed in the following reaction is:

In a multielectron atom, which of the following orbitals described by three quantum numbers will have the same energy in absence of electric and magnetic fields?
A. \( n = 1, l = 0, m_l = 0 \)
B. \( n = 2, l = 0, m_l = 0 \)
C. \( n = 2, l = 1, m_l = 1 \)
D. \( n = 3, l = 2, m_l = 1 \)
E. \( n = 3, l = 2, m_l = 0 \)
Choose the correct answer from the options given below: