The Gattermann-Koch reaction is a method used for the formylation of aromatic compounds, meaning the introduction of a formyl group (\( -CHO \)) to an aromatic ring. This reaction is particularly useful in organic synthesis for the preparation of aromatic aldehydes.
The general reaction is as follows:
\[
\text{Aromatic compound} + \text{CO} + \text{HCl} \xrightarrow{\text{AlCl}_3 \, \text{or} \, \text{CuCl}} \text{Aromatic aldehyde}.
\]
This reaction uses carbon monoxide (CO) and hydrogen chloride (HCl) in the presence of a Lewis acid catalyst such as AlCl\(_3\) or CuCl.
Step 1: Reaction Mechanism.
In the presence of the catalyst, carbon monoxide and hydrogen chloride react to form a reactive electrophilic species, \( \text{COCl}^+ \), which then attacks the aromatic ring to introduce the formyl group (\( -CHO \)).
Step 2: Example Reaction.
For instance, when benzene (\( \text{C}_6\text{H}_6 \)) reacts with carbon monoxide and hydrogen chloride in the presence of AlCl\(_3\) (a common Lewis acid), the product formed is benzaldehyde (\( \text{C}_6\text{H}_5\text{CHO} \)):
\[
\text{C}_6\text{H}_6 + \text{CO} + \text{HCl} \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{CHO}.
\]
Conclusion:
Thus, the Gattermann-Koch reaction is a formylation reaction where a **formyl group** (\( -CHO \)) is introduced to an aromatic ring, as described in option \( \mathbf{(A)} \).
Thus, the correct answer is \( \mathbf{(A)} \).