Which of the following pairs of ions will have same spin only magnetic moment values within the pair?
A. Zn2+, Ti2+
B. Cr2+, Fe2+
C. Ti3+, Cu2+
D. V2+, Cu+
Choose the correct answer from the options given below:
A. Zn2+, Ti2+
B. Cr2+, Fe2+
C. Ti3+, Cu2+
D. V2+, Cu+
Choose the correct answer from the options given below:
- C and D only
- A and D only
- A and B only
- B and C only
The Correct Option is D
Solution and Explanation
Spin-only magnetic moment is calculated using the formula:
\[\mu = \sqrt{n(n+2)}\]
where n is the number of unpaired electrons and μ is the magnetic moment in Bohr magnetons.
We need to determine the number of unpaired electrons for each ion:
- Zn2+ (d10), Ti2+ (d2): Zn2+ has 0 unpaired electrons, Ti2+ has 2.
- Cr2+ (d4), Fe2+ (d6): Cr2+ has 4 unpaired electrons, Fe2+ has 4.
- Ti3+ (d1), Cu2+ (d9): Ti3+ has 1 unpaired electron, Cu2+ has 1.
- V2+ (d3), Cu+ (d10): V2+ has 3 unpaired electrons, Cu+ has 0.
Therefore, the pairs with the same spin-only magnetic moment are B (Cr2+ and Fe2+) and C (Ti3+ and Cu2+).
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