Step 1: The efficiency (\( \eta \)) of an electric motor is given by: \[ \eta = \frac{\text{Output Power}}{\text{Input Power}} \times 100% \]
Step 2: Larger motors generally have higher full-load efficiency because: - Larger motors operate with lower relative losses. - Copper and iron losses are better managed. - Stray losses become negligible compared to output power.
Step 3: The efficiency of small motors (e.g., 1 kW or 5 kW) is lower due to: - Higher friction and windage losses. - Larger percentage of stray losses.
Step 4: Among the given options, the 100 kW motor has the highest expected full-load efficiency due to better energy conversion and reduced relative losses.
Parameters of the transistor shown in the circuit below are $\beta=100$, $I_{Cq} = 1$ mA.
Input resistance $R_i$ of the circuit is:
Consider the circuit shown in the below Figure and its load line characteristic. The x-intercept of the load line is
For the circuit shown in the Figure below, \(g_m\) of the transistor is
A closed-loop system has the characteristic equation given by: $ s^3 + k s^2 + (k+2) s + 3 = 0 $.
For the system to be stable, the value of $ k $ is:
A digital filter with impulse response $ h[n] = 2^n u[n] $ will have a transfer function with a region of convergence.