Question:

Which of the following motors is expected to have maximum full-load efficiency?

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Larger motors tend to have higher full-load efficiency because losses form a smaller fraction of the total power output.
Updated On: Feb 10, 2025
  • \( 1 \, \text{kW} \)
  • \( 5 \, \text{kW} \)
  • \( 30 \, \text{kW} \)
  • \( 100 \, \text{kW} \)
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The Correct Option is D

Solution and Explanation

Step 1: The efficiency (\( \eta \)) of an electric motor is given by: \[ \eta = \frac{\text{Output Power}}{\text{Input Power}} \times 100% \] 
Step 2: Larger motors generally have higher full-load efficiency because: - Larger motors operate with lower relative losses. - Copper and iron losses are better managed. - Stray losses become negligible compared to output power. 
Step 3: The efficiency of small motors (e.g., 1 kW or 5 kW) is lower due to: - Higher friction and windage losses. - Larger percentage of stray losses. 
Step 4: Among the given options, the 100 kW motor has the highest expected full-load efficiency due to better energy conversion and reduced relative losses.

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