Question:

Which of the following ligands forms a chelate complex?

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Chelate complexes are more stable because they form cyclic structures that resist ligand dissociation.
Updated On: Feb 25, 2025
  • C\(_2\)O\(_4^{2-}\)
  • Cl\(^{-}\)
  • NO\(_2^{-}\)
  • NH\(_3\)
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The Correct Option is A

Solution and Explanation

The oxalate ion (C\(_2\)O\(_4^{2-}\)) is a bidentate ligand, meaning it can coordinate to a metal ion at two different sites (via two oxygen atoms), forming a stable five-membered chelate ring. - Chelation increases stability of the metal complex due to the chelate effect, which is an entropy-driven stabilization phenomenon. - Common metal-oxalate complexes include: - [Fe(C\(_2\)O\(_4\))\(_3\)]^{3-} (Ferric oxalate) - [Cr(C\(_2\)O\(_4\))\(_3\)]^{3-} (Chromium(III) oxalate)
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