Question:
Which of the following ligands forms a chelate complex?
Which of the following ligands forms a chelate complex?
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Chelate complexes are more stable because they form cyclic structures that resist ligand dissociation.
Updated On: Feb 25, 2025
- C\(_2\)O\(_4^{2-}\)
- Cl\(^{-}\)
- NO\(_2^{-}\)
- NH\(_3\)
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The Correct Option is A
Solution and Explanation
The oxalate ion (C\(_2\)O\(_4^{2-}\)) is a bidentate ligand, meaning it can coordinate to a metal ion at two different sites (via two oxygen atoms), forming a stable five-membered chelate ring.
- Chelation increases stability of the metal complex due to the chelate effect, which is an entropy-driven stabilization phenomenon.
- Common metal-oxalate complexes include:
- [Fe(C\(_2\)O\(_4\))\(_3\)]^{3-} (Ferric oxalate)
- [Cr(C\(_2\)O\(_4\))\(_3\)]^{3-} (Chromium(III) oxalate)
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