Question:

Which of the following is the correct comparison of the stability of the molecules?

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In molecular orbital theory, H\(_2^{+}\) has a higher bond order than He\(_2^{+}\), making it more stable.
Updated On: Jan 6, 2026
  • CN\(^{+}\)<O\(_2^{+}\)
  • CN = N\(_2\)
  • N\(_2\)<O\(_2\)
  • H\(_2^{+}\)>He\(_2^{+}\)
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The Correct Option is D

Solution and Explanation

Step 1: Understand the molecular comparison.
Comparing the stability of diatomic molecules or ions, H\(_2^{+}\) is more stable than He\(_2^{+}\) due to the higher bond order in H\(_2^{+}\).
Step 2: Conclusion.
Thus, the correct answer is (D) H\(_2^{+}\)>He\(_2^{+}\).
Final Answer: \[ \boxed{D} \]
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