In an FCC lattice, there are 4 atoms per unit cell. The number of octahedral voids equals the number of atoms (4), and the number of tetrahedral voids is twice the number of atoms (8), so they are not equal (ruling out option 1). Tetrahedral voids are located along the body diagonals, not at the edge centers, which are occupied by atoms (ruling out option 2). Octahedral voids are indeed located at the body center (1/2, 1/2, 1/2) and edge centers (e.g., 1/2, 0, 0), making option 3 correct. Finally, the packing efficiency of FCC and HCP lattices is the same (74%), so option 4 is incorrect.
Thus, the correct answer is option 3.