Question:

Which of the following has an expanded octet?

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For elements in the third period and beyond, look for those that can have an expanded octet, as they have available d-orbitals to accommodate extra electrons.
Updated On: Apr 25, 2025
  • NH\(_3\)
  • H\(_2\)SO\(_4\)
  • SF\(_4\)
  • BeCl\(_2\)
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The Correct Option is C

Solution and Explanation


An expanded octet occurs when an atom has more than 8 electrons in its valence shell. This typically happens for atoms in the third period or higher, which have available d-orbitals that can accommodate more than 8 electrons. - NH\(_3\) (Ammonia): The nitrogen atom in NH₃ follows the octet rule with 8 electrons in its valence shell. - H\(_2\)SO\(_4\) (Sulfuric acid): The sulfur atom in H₂SO₄ does not have an expanded octet. It follows the octet rule with 8 electrons in its valence shell. - SF\(_4\) (Sulfur tetrafluoride): The sulfur atom in SF₄ has an expanded octet, with 10 electrons in its valence shell. This is possible because sulfur is in period 3 and can use d-orbitals to accommodate more electrons. - BeCl\(_2\) (Beryllium chloride): Beryllium typically does not expand its octet and follows the octet rule, having only 4 electrons in its valence shell. Thus, SF₄ is the correct answer as it has an expanded octet.
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