Which of the following halides cannot be hydrolysed ?
- CCl4
- SiCl4
- GeCl4
- SnCl4
The Correct Option is A
Approach Solution - 1
CCl₄ (Carbon tetrachloride) is a non-polar molecule and does not undergo hydrolysis. It is chemically inert to water because carbon does not have a strong enough ability to form bonds with water molecules, and C-Cl bonds are relatively stable.
SiCl₄ (Silicon tetrachloride), GeCl₄ (Germanium tetrachloride), and SnCl₄ (Tin tetrachloride) are metal halides that readily undergo hydrolysis. They react with water to form the corresponding metal hydroxides and hydrochloric acid (HCl):
- \(SiCl₄ + 4H₂O → Si(OH)₄ + 4HCl\)
- \(GeCl₄ + 4H₂O → Ge(OH)₄ + 4HCl\)
- \(SnCl₄ + 4H₂O → Sn(OH)₄ + 4HCl\)
Thus, CCl₄ does not undergo hydrolysis, making (A) the correct answer.
Approach Solution -2
CCl₄ (carbon tetrachloride) does not hydrolyse in water because it is a non-polar molecule and does not react with water. However, SiCl₄, GeCl₄, and SnCl₄ are more reactive and undergo hydrolysis to form silicates, germanates, and stannates, respectively.
Top Questions on p -Block Elements
- Which acid is the strongest: HF, HCl, HBr, HI?
- AIIMS Paramedical - 2025
- Chemistry
- p -Block Elements
- Oxidation numbers of oxygen in H_2O_2 and H_2O:
- AIIMS Paramedical - 2025
- Chemistry
- p -Block Elements
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- p -Block Elements
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- p -Block Elements
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
- JEE Main - 2025
- Chemistry
- p -Block Elements
Questions Asked in KCET exam
- If the number of terms in the binomial expansion of \((2x + 3)^n\) is 22, then the value of \(n\) is:
- KCET - 2025
- Binomial theorem
- Ethyl alcohol is heated with concentrated sulphuric acid at 413 K (140°C). The major product formed is
- KCET - 2025
- Organic Chemistry
- A body of mass 0.25 kg travels along a straight line from \( x = 0 \) to \( x = 2 \, \text{m} \) with a speed \( v = k x^2 \) where \( k = 2 \, \text{m}^{-1} \). The work done by the net force during this displacement is
- KCET - 2025
- Elastic and inelastic collisions
- A square loop of side 2 m lies in the Y-Z plane in a region having a magnetic field \(\mathbf{B} = (5 \hat{i} - 3 \hat{j} - 4 \hat{k}) \, \text{T}\). The magnitude of magnetic flux through the square loop is
- KCET - 2025
- Magnetic Field
- A random experiment has five outcomes \(w_1, w_2, w_3, w_4, w_5\). The probabilities of the occurrence of the outcomes \(w_1, w_2, w_4, w_5\) are respectively \( \frac{1}{6}, a, b, \frac{1}{12} \) such that \(12a + 12b - 1 = 0\). Then the probabilities of occurrence of the outcome \(w_3\) is:
- KCET - 2025
- Probability