The relationship between the radius \( R \) of a nucleus and its mass number \( A \) is given by the empirical formula:
\[
R = R_0 A^{1/3},
\]
where \( R_0 \) is a constant.
Taking the natural logarithm of both sides, we get:
\[
\ln \left( \frac{R}{R_0} \right) = \frac{1}{3} \ln A.
\]
This shows that the graph of \( \ln \left( \frac{R}{R_0} \right) \) versus \( \ln A \) is a straight line with a slope of \( \frac{1}{3} \). Thus, the correct option is the one that shows a straight line.