$OF_2$ dissolves in water but does not give any oxyacid solution. While $SO_2, SCl_4$ and $SO_3$ give oxyacid solution in water.
$ {SO_2 + H_2O ->$\underset{\mathrm{ Sulphurous acid }}{ { H_2SO_3 }}$}$
$ {SCl_4 + 3H_2O ->$\underset{\mathrm{ Sulphurous acid }}{ { H_2SO_3 }}$ + 4HCl}$
$ {SO_2 + H_2O ->$\underset{\mathrm{ Sulphurous acid }}{ { H_2SO_4 }}$}$