Question

Which of the following converts \(CH_3CONH_2\) to \(CH_3NH_2\)?

• A. NaBr
• B. NaOBr
• C. \(Br_2\)
• D. None of the above

Hint:

Hofmann bromamide reaction: \(RCONH_2 \xrightarrow{Br_2/NaOH} RNH_2\) (one carbon less). The active reagent is \(NaOBr\).

Answer 1

The Correct Option is B

Step 1: Identify required conversion.
\[ CH_3CONH_2 \rightarrow CH_3NH_2 \] This is conversion of an amide to an amine with one carbon less.
Step 2: Name of reaction.
This is Hofmann bromamide reaction (Hofmann rearrangement).
Step 3: Reagent used.
Hofmann rearrangement uses \(Br_2\) in presence of strong base \((NaOH)\) which forms \(NaOBr\) in situ.
Thus reagent is \(NaOBr\).
Final Answer: \[ \boxed{NaOBr} \]