Step 1: Use molecular geometry.
CCl$_4$ is perfectly tetrahedral and all C–Cl bond dipoles cancel due to symmetry. Step 2: Eliminate others.
CH$_3$Cl, CHCl$_3$, and CH$_2$Cl$_2$ are polar because the vector sum of their bond moments is non-zero. Step 3: Conclusion.
Hence, CCl$_4$ has zero dipole moment.
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