Step 1: Kolbe Electrolysis.
In Kolbe's electrolysis of an ester like ethyl propionate, two molecules of the ester undergo decarboxylation at the anode, leading to the formation of alkanes. The reaction does not form ethylene as ethylene is an unsaturated compound, and Kolbe's electrolysis typically forms saturated alkanes.
Step 2: Formation of Alkanes.
During the electrolysis, products such as n-butane, n-propane, and ethane can form due to the decarboxylation of the ester, but ethylene does not appear.
Step 3: Conclusion.
Hence, ethylene is not formed during Kolbe's electrolysis of ethyl propionate. The correct answer is (3) Ethylene.
Final Answer: \[ \boxed{\text{(3) Ethylene}} \]
The reaction is carried out by:
Which of the following amino compound(s) CANNOT be prepared by Gabriel phthalimide synthesis?
(A) n-Butylamine
(B) Alanine
(C) Aniline
(D) t-Butylamine
Choose the correct answer from the options given below:
The final product (D) in the above sequential reaction is:
The major product (P) in the following transformation is:
Above conversion is carried out using:
Match List-I with List-II and choose the correct answer:
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