Question

Above conversion is carried out using: 

• A. (I) KOH (alc.), (II) oxymurcuration-demercuration
• B. (I) KOH (aq.), (II) Conc. H\(_2\)SO\(_4\)
• C. (I) KOH (alc.), (II) Hydroboration-oxidation
• D. (I) Nucleophilic addition-elimination, (II) oxymurcuration-demercuration

Hint:

The oxymurcuration-demercuration sequence involves hydration of alkenes using mercuric acetate followed by reduction with sodium borohydride.

Answer 1

The Correct Option is A

Step 1: KOH (alc.).
Potassium hydroxide in alcohol (KOH (alc.)) induces elimination of the bromine atom, producing an alkene.

Step 2: Oxymurcuration-demercuration.
The alkene then undergoes oxymurcuration-demercuration to form an alcohol at the position where the bromine was originally attached. Hence, option (1) is correct.

Final Answer: \[ \boxed{\text{(1) (I) KOH (alc.), (II) oxymurcuration-demercuration}} \]