The probability of an event must always be a number between 0 and 1, inclusive. This means that: \[ 0 \leq \text{Probability of an event} \leq 1. \] Now, let's evaluate each option:
\( \frac{1}{3} \) is a valid probability because it lies between 0 and 1.
0.3 is a valid probability because it is between 0 and 1.
33% is equivalent to \( \frac{33}{100} \), which is a valid probability because it lies between 0 and 1.
\( \frac{7}{6} \) is greater than 1, which is not a valid probability.
The correct option is (D): \(\frac{7}{6}\)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)