Question:

Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species $O^{2-}, S^{2-}, N^{3-}, P^{3-} ?$

Updated On: Sep 24, 2024
  • $O^{2-} < N^{3-} < S^{2-} < P^{3-}$
  • $O^{2-} < P^{3-} < N^{3-} < S^{2-}$
  • $N^{3-} < O^{2-} < P^{3-} < S^{2-}$
  • $N^{3-} < S^{2-} < O^{2-} < P^{3-}$
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The Correct Option is A

Solution and Explanation

For isoelectronic species ionic radii decreases as the charge on ion decreases. Further on moving down in a group ionic radii increases. Hence the correct order is
$O^{2-} < N^{3-} < S^{2-} < P^{3-}$
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Concepts Used:

Haloalkanes and Haloarenes - Classification

Classification of Haloalkanes and Haloarenes are as follows:

Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:

These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;

  • Monohaloalkane
  • Dihaloalkane
  • Trihaloalkane

Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)

This class includes:

  • Alkyl halides or haloalkanes (R—X)
  • Allylic halides
  • Benzylic halides

Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond

This class includes:

  • Vinylic halides
  • Aryl halides