Anti-Markovnikov addition occurs when HBr adds to an alkene such that the hydrogen atom attaches to the carbon atom with the fewest alkyl groups, resulting in the formation of the less stable carbocation. This addition typically occurs with peroxides (as in the case of the anti-Markovnikov mechanism).
Step 1: Propene (C$_3$H$_6$) undergoes anti-Markovnikov addition of HBr in the presence of peroxides. In this reaction, the hydrogen adds to the carbon with fewer alkyl groups, and the bromine adds to the carbon with more alkyl groups.
Step 2: 1-Butene (C$_4$H$_8$) also undergoes anti-Markovnikov addition of HBr in the presence of peroxides, similar to propene.
Step 3: 2-Butene (C$_4$H$_8$) undergoes Markovnikov addition of HBr, where the bromine atom attaches to the carbon with more alkyl groups, and the hydrogen attaches to the carbon with fewer alkyl groups. Therefore, 2-Butene does not undergo anti-Markovnikov addition.
Step 4: 3-Methyl-2-pentene (C$_6$H$_{12}$) undergoes Markovnikov addition and does not follow the anti-Markovnikov addition rule.
Thus, the correct answer is 2-Butene, which does not undergo anti-Markovnikov addition.
Arrange the following in decreasing order of their basicity:
Arrange the following in increasing order of their pK\(_b\) values.
What is Z in the following set of reactions?
Acetophenone can be prepared from which of the following reactants?
What are \(X\) and \(Y\) in the following reactions?
What are \(X\) and \(Y\) respectively in the following reaction?