Question:

Which of the following 3d-metal ion will give the lowest enthalpy of hydration (ΔhydH) when dissolved in water?

Updated On: Dec 29, 2025
  • Cr2+

  • Mn2+

  • Fe2+

  • Co2+

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The Correct Option is B

Approach Solution - 1

The enthalpy of hydration (\(\Delta_{\text{hyd}}H\)) of metal ions is influenced by their charge and ionic radius. A higher charge and smaller ionic radius generally lead to a more negative (stronger) \(\Delta_{\text{hyd}}H\), due to stronger interaction with water molecules.

Let's evaluate the 3d-metal ions given:

  1. Cr2+: Charge = +2, Atomic number = 24, Configuration [Ar] 3d
  2. Mn2+: Charge = +2, Atomic number = 25, Configuration [Ar] 3d5
  3. Fe2+: Charge = +2, Atomic number = 26, Configuration [Ar] 3d6
  4. Co2+: Charge = +2, Atomic number = 27, Configuration [Ar] 3d7

The strength of hydration depends upon the size and electronic configuration of the ion:

  • Manganese, Mn2+ has a half-filled 3d5 electron configuration, making it relatively stable and thus, has lower enthalpy of hydration.
  • Other ions (Cr2+, Fe2+, Co2+) do not have especially stable symmetric configurations like Mn2+.

Since Mn2+ with its half-filled d-orbital configuration is more stable, it gives the lowest enthalpy of hydration when compared to other metal ions with full or partially filled d-orbitals.

Conclusion: Among the given options, Mn2+ will give the lowest \(\Delta_{\text{hyd}}H\) when dissolved in water due to its stable half-filled electronic configuration, leading to weaker interactions with water molecules.

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Approach Solution -2

 Δhyd H (M+2)
Cr– 1925
Mn– 1862
Fe– 1560
Co– 1640

 


Mn2+ has the lowest ΔhydH.
So, the correct option is (B): Mn2+

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Top Questions on Enthalpy change

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Concepts Used:

Enthalpy change

Enthalpy Change refers to the difference between the heat content of the initial and final state of the reaction. Change in enthalpy can prove to be of great importance to find whether the reaction is exothermic or endothermic.

Formula for change in enthalpy is:-

dH = dU + d(PV)

The above equation can be written in the terms of initial and final states of the system which is defined below:

UF – UI = qP –p(VF – VI)

Or qP = (UF + pVF) – (UI + pVI)

Enthalpy (H) can be written as H= U + PV. Putting the value in the above equation, we obtained: 

qP = HF – HI = ∆H

Hence, change in enthalpy ∆H = qP, referred to as the heat consumed at a constant pressure by the system. At constant pressure, we can also write,

∆H = ∆U + p∆V

Standard Enthalpy of Reaction

To specify the standard enthalpy of any reaction, it is calculated when all the components participating in the reaction i.e., the reactants and the products are in their standard form. Therefore the standard enthalpy of reaction is the enthalpy change that occurs in a system when a matter is transformed by a chemical reaction under standard conditions.