Question

Which number is obtained when the 18th number from the right end is added to the 19th number from the left end of the series?

6 7 8 9 8 9 8 7 9 7 7 8 9 7 8 7 6 9 6 8 9 7 7 9 8 9 7 7 6 6 8 7

• A. 17
• B. 15
• C. 16
• D. 14

Hint:

For “$k$th from right” in a list of $N$, convert to “from left” via $N-k+1$ (1-based indexing), then pick the values and operate.

Answer 1

The Correct Option is D

Step 1: Fix positions (1-based).
The series has $32$ terms.
19th from the left $⇒$ position $19$.
18th from the right $⇒$ position $32-18+1=15$ from the left.
Step 2: Read the required terms.
Position $15 = 8$; Position $19 = 6$ (from the written series).
Step 3: Add them.
$8 + 6 = 14$. \[ \boxed{14} \] Note: With the series exactly as printed above, the computed sum is $14$, which does not appear among the options (17, 15, 16, 18). If the source expects a listed option, please re-check the series digits around positions $15$–$20$ for a possible misprint.