Question:
Which is not the unit of electric field?
Which is not the unit of electric field?
Updated On: May 19, 2022
- $ \frac{N}{C} $
- $ \frac{N-m}{C} $
- $ \frac{V}{m} $
- $ \frac{J}{C-m} $
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The Correct Option is B
Solution and Explanation
The electric field [E] intensity is given by
$ E=-\frac{dV}{dx} $
Its unit is V/m.
Also, $ F=qE $
$ \Rightarrow $ $ E=\frac{F}{q} $
Hence, unit of E is $ \frac{N}{C} $
Also $ E=\frac{W}{qx} $
Hence unit is $ \frac{J}{C-m} $
$ E=-\frac{dV}{dx} $
Its unit is V/m.
Also, $ F=qE $
$ \Rightarrow $ $ E=\frac{F}{q} $
Hence, unit of E is $ \frac{N}{C} $
Also $ E=\frac{W}{qx} $
Hence unit is $ \frac{J}{C-m} $
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Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).