Question:
Which is incorrect statement regarding $ {B_2H_6}$ ?
Which is incorrect statement regarding $ {B_2H_6}$ ?
Updated On: Jul 7, 2022
- It is a strong reducing agent
- On heating, it gives amorphous boron
- It is a planar molecule
- With excess $\ce{(CH_3)_3N}$, it undergoes symmetrical cleavage
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The Correct Option is C
Solution and Explanation
Four $H_t$ and two $B$ atoms lie in the same plane while two bridging H atoms $(H_b)$ lie in a plane perpendicular to the rest of the molecule. Thus, $ {B_2H_6}$ is not a planar molecule.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family