Question:

Which has maximum number of atoms?

Updated On: Aug 29, 2023
  • 24 g of C (12)
  • 56 g of Fe (56)
  • 27 g of A1 (27)
  • 108 g of Ag (108)
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The Correct Option is A

Approach Solution - 1

The correct answer is A:24g of C(12)
Number of atoms = Number of moles 
\(\times\) Avogadro's number \((N_A)\)
Number of atoms in 24 g C = \(\frac{ 24}{12} \times N_A = 2N_A\) 
Number of atoms in 56 g of Fe = \(\frac{ 56}{56}N_A = N_A\) 
Number of atoms in 27 g of Al = \(\frac{27}{27}N_A = N_A\) 
Number of atoms in 108 g of Ag = \(\frac{108}{108} N_A = N_A\) 
Hence, 24 g of carbon has the maximum number of atoms.
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Approach Solution -2

1 mole contains Na number of atoms. Na is the avogadro's number. 
Molar mass of C is 12g, which means 12g of C contains Na atoms. 
Therefore, 24g of C contains 2 x Na
On the other hand, 
Molar mass of Fe is 56g, Al is 27g and Ag is 108. 
Therefore, they all contains Na number of atoms. 
So, the maximum number of atoms are present in 24g of C.
 
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