Question:

Which element belongs to $4n$ series?

Updated On: Jul 2, 2022
  • $ Pb^{207}$
  • $ Bi^{209}$
  • $ Pb^{208}$
  • $ Pb^{206}$
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The Correct Option is C

Solution and Explanation

Series of an element is decided by dividing its atomic mass by $4$. In case of $4\, n$ series, the remainder is zero. This is true only in case of $Pb ^{208}$. Thus, $Pb ^{208}$ belongs to $4\, n$ series.
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: