Question:

Which compound decolorizes iodine solution?

Updated On: Aug 1, 2022
  • $H _{2} SO _{4}$
  • $N a_{2} S$
  • $Na _{2} SO _{4}$
  • $Na _{2} S _{2} O _{3}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Hypo $\left( Na _{2} S _{2} O _{3}\right)$ decolourises iodine solution. $2 Na _{2} S _{2} O _{3}+ I _{2} \longrightarrow 2 NaI + \underset{\text{Sodium tetra thionate}}{Na _{2} S _{4} O _{6}}$
Was this answer helpful?
0
0

Concepts Used:

Group 17 Elements

Halogens are the group 17 elements of the periodic table. The term ‘halogen’ means ‘salt-producing’, hence the name halogens as they possess the tendency to form salts after reacting to metals. It generally has five elements:

  • Fluorine (F)
  • Chlorine (Cl)
  • Bromine (Br)
  • Iodine (I)
  • Astatine (At)

These are all naturally occurring halogens but Tennessine (Ts) is an artificially created halogen.

Halogens:

Halogens are highly reactive elements and are highly electronegative. They have a high tendency to react with metals to form salts. They are also known as Group 17 elements. They have 7 electrons in their outer shell with a configuration of (ns2 np5). Fluorine being the first halogen in group 17, is highly reactive. Astatine is a halogen because of its resemblance with iodine despite it being radioactive.

Electronic Configuration:

The general electronic configuration for group 17 elements is ns2np5. This configuration clearly shows that they have 7 electrons in their valence shell. They require one more electron to complete their octet and achieve noble gas configuration.