Question

Which complex has dsp$^2$ hybridisation?

• A. \( [Ni(CN)_4]^{2-} \)
• B. \( BF_4^- \)
• C. \( BF_2^- \)
• D. \(NH_2\)

Hint:

When determining hybridization, focus on the number of electron pairs around the central atom and the geometry of the complex. For square planar geometries, \( dsp^2 \) hybridization is common.

Answer 1

The Correct Option is A

To determine the hybridization, we need to examine the geometry and electronic configuration of the central metal ion. - In \( [Ni(CN)_4]^{2-} \), the nickel ion has a \( +2 \) charge. The \( CN^- \) ligands are strong field ligands and will cause pairing of electrons. The resulting hybridization of the nickel ion in this complex is \( dsp^2 \), corresponding to a square planar geometry. - On the other hand, \( BF_4^- \) involves a central boron ion with no d-orbitals involved, and it has an sp\(^3\) hybridization.
Thus, the correct complex with dsp\(^2\) hybridization is \( [Ni(CN)_4]^{2-} \), so the correct answer is \( A \).