The \(\text{I}_3^-\) ion exhibits a linear geometry due to its electronic arrangement. According to the Valence Shell Electron Pair Repulsion (VSEPR) theory:
The central iodine atom in \(\text{I}_3^-\) has three lone pairs of electrons and forms bonds with two outer iodine atoms.
The lone pairs arrange symmetrically to minimize electron repulsion, resulting in a bond angle of \(180^\circ\).
This linear geometry is a characteristic of triatomic species with symmetric electron distribution.
\(1\,\text{g}\) of \( \mathrm{AB_2} \) is dissolved in \(50\,\text{g}\) of a solvent such that \( \Delta T_f = 0.689\,\text{K} \). When \(1\,\text{g}\) of \( \mathrm{AB} \) is dissolved in \(50\,\text{g}\) of the same solvent, \( \Delta T_f = 1.176\,\text{K} \). Find the molar mass of \( \mathrm{AB_2} \). Given \( K_f = 5\,\text{K kg mol}^{-1} \). \((\textit{Report to nearest integer.})\) Both \( \mathrm{AB_2} \) and \( \mathrm{AB} \) are non-electrolytes.