Step 1: Brewster's Angle
According to Brewster's law, the angle of incidence \( \theta_i \) at which the reflected light is completely polarized is called Brewster's angle \( \theta_B \). Brewster's angle is given by:
\[
\tan \theta_B = \frac{n_2}{n_1}
\]
where \( n_1 \) is the refractive index of the first medium (air) and \( n_2 \) is the refractive index of the second medium (the transparent medium).
In air, \( n_1 \approx 1 \), so the equation simplifies to:
\[
\tan \theta_B = n_2
\]
Step 2: Relationship Between Incident and Refracted Angles
According to Snell's law, the relationship between the angles of incidence and refraction is given by:
\[
\frac{\sin \theta_i}{\sin \theta_r} = \frac{n_2}{n_1}
\]
where \( \theta_i = 60^\circ \), and \( \theta_r \) is the angle of refraction.
Step 3: Brewster's Angle for Complete Polarization
When the reflected ray is completely polarized, the angle of incidence \( \theta_i = 60^\circ \) must equal the Brewster's angle \( \theta_B \). Therefore, the angle of refraction \( \theta_r \) is:
\[
\theta_r = 30^\circ
\]
Final Answer: The angle of refraction in the medium is \( 30° \).