Question

When the valence d orbitals of the central metal ion in tetrahedral complex are split in energy levels in CFT, which orbitals are raised to higher energy?

• A. Dxy, dxz, and dyz
• B. Dxy and dx2 -y2
• C. Dxz and dyz
• D. Dx2-y2 and dz2

Answer 1

The Correct Option is A

To solve the problem, we need to determine which valence d orbitals of the central metal ion in a tetrahedral complex are raised to higher energy when split in Crystal Field Theory (CFT).

1. Understanding the Tetrahedral Crystal Field Splitting:
In a tetrahedral complex, the central metal ion is surrounded by four ligands arranged tetrahedrally. The d orbitals of the metal ion split into two energy levels due to the interaction with the ligands.

2. Identifying the Higher Energy Orbitals:
In a tetrahedral field, the d orbitals split into two groups:

• Lower energy (e): The $d_{x^2-y^2}$ and $d_{z^2}$ orbitals (collectively referred to as the $e$ set) experience less repulsion from the ligands and are stabilized.
• Higher energy (t₂): The $d_{xy}$, $d_{xz}$, and $d_{yz}$ orbitals (collectively referred to as the $t_2$ set) experience greater repulsion from the ligands and are raised to higher energy.

3. Correct Option:
From the given choices, the orbitals raised to higher energy are $d_{xy}$, $d_{xz}$, and $d_{yz}$.

Final Answer:
The correct option is $\boxed{D_{xy}, D_{xz}, \text{ and } D_{yz}}$.