Question:
When the radioactive isotope \(_{88}Ra^{226}\) decays in a series by emission of three alpha \((α)\) and a beta \((β)\) particle, the isotope \(X\) which remains undecay is
When the radioactive isotope \(_{88}Ra^{226}\) decays in a series by emission of three alpha \((α)\) and a beta \((β)\) particle, the isotope \(X\) which remains undecay is
Updated On: Jun 21, 2024
- \(_{83}X^{214}\)
- \(_{84}X^{218}\)
- \(_{84}X^{220}\)
- \(_{87}X^{223}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(_{83}X^{214}\).
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