To solve this problem, we need to balance the chemical equation:
1. Given Reaction:
The unbalanced equation is:
\( \text{Na} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \)
2. Balancing the Equation:
- Sodium (Na) reacts with water (H2O) to form sodium hydroxide (NaOH) and hydrogen gas (H2).
- To balance, we start by balancing hydrogen (H). On the right side, there is 1 molecule of H2, which provides 2 hydrogen atoms. Therefore, we need 2 NaOH on the left.
- Now, we balance sodium (Na). Since there are 2 sodium atoms in 2 NaOH, we need 2 sodium atoms on the left, i.e., 2 Na.
- Lastly, oxygen (O) is already balanced as it appears once on both sides.
3. The Balanced Equation:
\( 2\text{Na} + 2\text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2 \)
4. Coefficient of Na:
The coefficient of Na (sodium) in the balanced equation is 2.
Final Answer:
The correct option is (A) 2.
In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is ___________%. [Given: Molar mass in g mol\(^{-1}\) of Ag = 108, Cl = 35.5]