Question:

When photons of energy hv fall on an aluminum plate (of work function E0), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be :

Updated On: Jun 23, 2024
  • K + E0
  • 2K
  • K
  • k + hv
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The Correct Option is D

Solution and Explanation

K=hv−E0
and K′=h(2v)−E0
=2hv−E0
=hv+hv−E0
K′= k + hv

Therefore, the correct option is (D): k + hv

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Concepts Used:

Dual Nature of Radiation and Matter

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Photoelectric Effect

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Heisenberg’s Uncertainty Principle

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