When photons of energy hv fall on an aluminum plate (of work function E0), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be :
- K + E0
- 2K
- K
- k + hv
The Correct Option is D
Solution and Explanation
K=hv−E0
and K′=h(2v)−E0
=2hv−E0
=hv+hv−E0
K′= k + hv
Therefore, the correct option is (D): k + hv
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Concepts Used:
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Electronic Emission
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Photoelectric Effect
The photoelectric effect is a phenomenon that involves electrons getting away from the surface of materials.
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Heisenberg’s Uncertainty Principle states that both the momentum and position of a particle cannot be determined simultaneously.