The question deals with the concept of reaction orders in physical chemistry, specifically focusing on cases where one reactant is in excess. Let's break down the solution:
In chemical kinetics, the order of a reaction is determined by how the rate of reaction depends on the concentration of the reactants. However, in some reactions, one reactant is present in such a large excess that its concentration does not significantly change during the reaction. This leads to the concept of pseudo-order reactions.
Pseudo-Order Reaction: When one reactant is present in a large excess, its concentration remains approximately constant throughout the reaction. Consequently, the reaction can be simplified to appear as if it is of a lower order than it actually is.
For example, consider a reaction that is normally second-order:
\(A + B \rightarrow \text{Products}\)
Under normal conditions, the rate equation is:
\(\text{Rate} = k[A][B]\)
If reactant \(B\) is in excess, its concentration remains nearly constant, and the rate equation simplifies to:
\(\text{Rate} = k' [A]\) where \(k' = k[B]\) (constant)
This effectively makes the reaction appear first-order with respect to reactant \(A\). This is an example of a pseudo-order reaction, specifically pseudo-first order in this case.
Now, let's evaluate the given options:
Conclusion: When one of the reactants is in great excess such that its concentration remains nearly constant, the reaction is described as a pseudo-order reaction. Thus, the correct answer is pseudo-order.
Match the following:
(P) Schedule H
(Q) Schedule G
(R) Schedule P
(S) Schedule F2
Descriptions:
(I) Life period of drugs
(II) Drugs used under RMP
(III) List of Prescription Drugs
(IV) Standards for surgical dressing
Choose the correct match of laxative and its Mechanism of Action (MOA):
