The question deals with the concept of reaction orders in physical chemistry, specifically focusing on cases where one reactant is in excess. Let's break down the solution:
In chemical kinetics, the order of a reaction is determined by how the rate of reaction depends on the concentration of the reactants. However, in some reactions, one reactant is present in such a large excess that its concentration does not significantly change during the reaction. This leads to the concept of pseudo-order reactions.
Pseudo-Order Reaction: When one reactant is present in a large excess, its concentration remains approximately constant throughout the reaction. Consequently, the reaction can be simplified to appear as if it is of a lower order than it actually is.
For example, consider a reaction that is normally second-order:
\(A + B \rightarrow \text{Products}\)
Under normal conditions, the rate equation is:
\(\text{Rate} = k[A][B]\)
If reactant \(B\) is in excess, its concentration remains nearly constant, and the rate equation simplifies to:
\(\text{Rate} = k' [A]\) where \(k' = k[B]\) (constant)
This effectively makes the reaction appear first-order with respect to reactant \(A\). This is an example of a pseudo-order reaction, specifically pseudo-first order in this case.
Now, let's evaluate the given options:
Conclusion: When one of the reactants is in great excess such that its concentration remains nearly constant, the reaction is described as a pseudo-order reaction. Thus, the correct answer is pseudo-order.
Match the following:
(P) Schedule H
(Q) Schedule G
(R) Schedule P
(S) Schedule F2
Descriptions:
(I) Life period of drugs
(II) Drugs used under RMP
(III) List of Prescription Drugs
(IV) Standards for surgical dressing