Photoelectron emission occurs when light of sufficient energy (frequency) strikes a metal surface, as per the photoelectric effect. The energy of a photon is given by \( E = h \nu \), where \( h \) is Planck's constant and \( \nu \) is the frequency of the incident light. For the photoelectric effect to occur, the frequency of the light must exceed a certain threshold frequency \( \nu_0 \), which corresponds to the work function of the metal.
- Blue light has a higher frequency than green and yellow light, and since it causes the emission of photoelectrons, it implies the energy of blue light is above the threshold.
- Green light has a lower frequency than blue light, and since it does not emit photoelectrons, it implies the energy of green light is below the threshold for this particular metal.
- Yellow light has a frequency slightly lower than blue but still might be above the threshold. If yellow light has the same or greater energy than the threshold, photoelectrons will be emitted in equal or lesser quantity as for blue light.
Thus, the number of photoelectrons emitted with yellow light will be equal to that emitted by blue light, assuming the energy of yellow light is sufficient to release photoelectrons.