Question:
When an ideal gas is compressed adiabatically, its temperature rises the molecules on the average have more kinetic energy than before. The kinetic energy increases
When an ideal gas is compressed adiabatically, its temperature rises the molecules on the average have more kinetic energy than before. The kinetic energy increases
Updated On: Jul 7, 2022
- because of collisions with moving parts of the wall only
- because of collisions with the entire wall
- because the molecules gets accelerated in their motion inside the volume
- because the redistribution of energy amongst the molecules
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
If an ideal gas is compressed adiabatically, its temperature rises, because heat produced cannot be lost to the surroundings. Each molecule has more $KE$ than before because of collisions of molecules with moving parts of the wall (i.e. piston compressing the gas).
Was this answer helpful?
0
0
Top Questions on kinetic theory
- Mean free path is inversely proportional to (n = number density, d = diameter of particle)
- KEAM - 2025
- Physics
- kinetic theory
- The equation for the RMS velocity is given as \[ v_{\text{rms}} = \sqrt{\frac{3RT}{M_0}} \] where \( R \) is the gas constant, \( T \) is the temperature, and \( M_0 \) is the molecular mass. If the temperature is increased, find the new RMS velocity \( v_{\text{rms}} \) when the temperature is doubled.}
- MHT CET - 2025
- Physics
- kinetic theory
The motion of a particle in the XY plane is given by \( x(t) = 25 + 6t^2 \, \text{m} \); \( y(t) = -50 - 20t + 8t^2 \, \text{m} \). The magnitude of the initial velocity of the particle, \( v_0 \), is given by:
- OJEE - 2024
- Physics
- kinetic theory
- A body of mass \( m \) moves along the X-axis such that at time \( t \), its position is \( x(t) = \alpha t^4 - \beta t^3 + \gamma t \), where \( \alpha \), \( \beta \), and \( \gamma \) are constants. The acceleration of the body is:
- OJEE - 2024
- Physics
- kinetic theory
- A stone is dropped from the top of a tower. The height through which it falls in the first 3 seconds of its motion equals the height through which it falls in the last second of its motion. To reach the ground, the stone takes time equal to (g = 10 m/s\(^2\)):
- OJEE - 2024
- Physics
- kinetic theory
View More Questions