When a spring is stretched by a distance $x$, it exerts a force, given by $F = (-5x - 16x^{3})\, N$. The work done, when the spring is stretched from $0.1 \,m$ to $0.2\, m $ is
- $8.7 \times 10^{-2}\,J$
- $12.2 \times 10^{-2}\, J$
- $8.7 \times 10^{-1}\,J$
- $12.2 \times 10^{-1}\,J$
The Correct Option is A
Solution and Explanation
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- Solutions
Concepts Used:
Work
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.
Work Formula:
W = Force × Distance
Where,
Work (W) is equal to the force (f) time the distance.
Work Equations:
W = F d Cos θ
Where,
W = Amount of work, F = Vector of force, D = Magnitude of displacement, and θ = Angle between the vector of force and vector of displacement.
Unit of Work:
The SI unit for the work is the joule (J), and it is defined as the work done by a force of 1 Newton in moving an object for a distance of one unit meter in the direction of the force.
Work formula is used to measure the amount of work done, force, or displacement in any maths or real-life problem. It is written as in Newton meter or Nm.