Question:

When a slow neutron is captured by a $^{235}_{92} U$ nucleus, a fission energy releasing $200\, MeV$. If power of nuclear reactor is $100\, W$ then rate of nuclear fission is

Updated On: Aug 1, 2022
  • $3.6 \times 10^6 \,s^{-1}$
  • $3.1 \times 10^{12}\,s^{-1}$
  • $1.8 \times 10^4\, s^{-1}$
  • $4.1 \times 10^6\, s^{-1}$
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The Correct Option is B

Solution and Explanation

Number of fission per second $=\frac{\text { totalpower }}{\text { energy/fission }}$ Here, total power $= 100\, W$ energy/fission $= 200\, MeV =200 \times 10^{6} \times 1.6 \times 10^{-19}\, J$ $=3.2 \times 10^{-11}\, J .$ $\therefore$ fission rate $=\frac{100}{3.2 \times 10^{-11}}=3.1 \times 10^{12} s ^{-1}$
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Concepts Used:

Nuclei

In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.

Read More: Nuclei

Following are the terms related to nucleus:

  1. Atomic Number
  2. Mass Number
  3. Nuclear Size
  4. Nuclear Density
  5. Atomic Mass Unit