Question:
When a proton is released from rest in a room, it starts with an initial acceleration $a_0$ towards west. When it is projected towards north with a speed $v_0$ it moves with an initial acceleration 3$a_0$ toward west. The electric and magnetic fields in the room
When a proton is released from rest in a room, it starts with an initial acceleration $a_0$ towards west. When it is projected towards north with a speed $v_0$ it moves with an initial acceleration 3$a_0$ toward west. The electric and magnetic fields in the room
Updated On: Apr 21, 2025
- $\frac{ma_0}{e}$ west $\frac{2ma_0}{ev_0}$ up
- $\frac{ma_0}{e}$ west $\frac{2ma_0}{ev_0}$ down
- $\frac{ma_0}{e}$ east $\frac{2ma_0}{ev_0}$ up
- $\frac{ma_0}{e}$ east $\frac{2ma_0}{ev_0}$ down
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The Correct Option is B
Solution and Explanation
The correct option is (B): $\frac{ma_0}{e}$ west $\frac{2ma_0}{ev_0}$ down
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