$-1.6 \times 10^{-15}$ C
Step 1: The charge on a single electron is: \[ e = 1.6 \times 10^{-19} { C} \]
Step 2: The charge on the glass rod is given by: \[ Q = n e \] where $n$ is the number of lost electrons. Given that $n = 1000$, we get: \[ Q = 1000 \times 1.6 \times 10^{-19} \] \[ Q = 1.6 \times 10^{-16} { C} \]
Step 3: Since the rod loses electrons, it becomes positively charged.
Step 4: Therefore, the correct answer is (A).
Match List - I with List - II:
List - I:
(A) Electric field inside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(B) Electric field at distance \( r > 0 \) from a uniformly charged infinite plane sheet with surface charge density \( \sigma \).
(C) Electric field outside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(D) Electric field between two oppositely charged infinite plane parallel sheets with uniform surface charge density \( \sigma \).
List - II:
(I) \( \frac{\sigma}{\epsilon_0} \)
(II) \( \frac{\sigma}{2\epsilon_0} \)
(III) 0
(IV) \( \frac{\sigma}{\epsilon_0 r^2} \) Choose the correct answer from the options given below: