Question:

When a galvanometer is shunted by resistance S, its current capacity increases n times. If the same galvanometer is shunted by another resistance S', its current capacity will increase by n' is given by

Updated On: Oct 1, 2024
  • $ \frac{(n+1)S}{S'} $
  • $ \frac{S(n-1)+S'}{S'} $
  • $ \frac{n+S}{S'} $
  • $ \frac{S(n-1)-S'}{S'} $
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The Correct Option is B

Solution and Explanation

Using the relation $ S=\frac{G}{(n-1)} $ $ \Rightarrow $ $ G=S(n-1) $ and $ S'\frac{G}{(n'-1)} $ $ \Rightarrow $ $ n'=\frac{G+S'}{S'} $ $ \therefore $ $ n'=\frac{S(n-1)+S'}{S'} $
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Concepts Used:

Electrical Instruments

There are various electrical instruments used to measure current, power, voltage, etc.  Some of them are briefly explained below:

Moving Coil Galvanometer

  • It is an electromagnetic device which measures small values of current.
  • Its working principle is that whenever a current loop is placed in a magnetic field, it experiences a certain torque. The value of that torque can be modified by modifying the current in the loop.
  • For a current carrying loop having N turns, and cross sectional area A, carrying current i, whenever it is placed in and along the direction of an external magnetic field B, it experiences a torque given by:

ԏ = NiAB

moving coil galvanometer