What will be the ratio of the distance moved by a freely falling body from rest in $4^{th}$ and $5^{th}$ seconds of journey ?
- 4 : 5
- 7 : 9
- 16 : 25
- 1 : 1
The Correct Option is B
Solution and Explanation
$ s_n = u +\frac{a}{2} (2n-1)$
Given : u = 0, a = g
$\therefore \, \, \, s_4 = \frac{g}{2} (2 \times 4-1)=\frac{7g}{2}$
$ s_5 = \frac{g}{2} (2 \times 5-1)=\frac{9g}{2} \, \, \, \, \, \therefore \frac{s_4}{s_5} =\frac{7}{9}$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.