Question

What was the day of the week on 28th May 2006?

• A. Thursday
• B. Friday
• C. Saturday
• D. Sunday

Hint:

Within a year, sum month-wise days up to the day before the target date and take modulo $7$; a remainder of $0$ means the same weekday as the reference.

Answer 1

The Correct Option is D

Step 1: Reference
Given: Jan 1, 2006 was Sunday. 2006 is not a leap year.
Step 2: Count days elapsed from Jan 1 to May 28
We count days up to the day before} May 28, i.e., through May 27.
Jan: $31$ days $31$
Feb: $28$ (non-leap) $31+28=59$
Mar: $31$ $59+31=90$
Apr: $30$ $90+30=120$
May: first $27$ days $120+27=\;147$ total days elapsed.
Step 3: Reduce modulo 7
$147 \div 7 = 21$ weeks, remainder $0$ same weekday as Jan 1.
Step 4: Conclude
Same as Sunday \boxed{\text{Sunday}}.
\[ \boxed{\text{Sunday (Option (d)}} \]