Question:
What volume of oxygen gas $(O_2)$ measured at $0^\circ C$ and 1 atm, is needed to bum completely 1L of propane gas $(C_3H_8)$ measured under the same conditions?
What volume of oxygen gas $(O_2)$ measured at $0^\circ C$ and 1 atm, is needed to bum completely 1L of propane gas $(C_3H_8)$ measured under the same conditions?
Updated On: Jul 26, 2024
- 7 L
- 6 L
- 5 L
- 10 L
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The Correct Option is C
Solution and Explanation
The correct answer is C:5L
\(C_3H_8 + \, \, \, 50 _2 \rightarrow 3CO_2 + 4H_2O\)
For the combustion of 22.4 L propane, oxygen required = \(5 \times 22.4 L\)
For the combustion of 1 L of propane oxygen required \(\frac {5 \times 22.4}{22.4}L\)
\( = 5 L\)
\(C_3H_8 + \, \, \, 50 _2 \rightarrow 3CO_2 + 4H_2O\)
For the combustion of 22.4 L propane, oxygen required = \(5 \times 22.4 L\)
For the combustion of 1 L of propane oxygen required \(\frac {5 \times 22.4}{22.4}L\)
\( = 5 L\)
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There are two ways of classifying the matter:
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