Step 1: Decarboxylation reaction:
\[
CH_3COONa + NaOH \rightarrow CH_4 + Na_2CO_3.
\]
Step 2: Molar mass sodium acetate = 82 g/mol.
\[
\text{mole}=\frac{8.2}{82}=0.1.
\]
Step 3: 1 mole salt → 1 mole CH$_4$.
Step 4: Volume at NTP:
\[
V=0.1\times22.4=2.24\text{ L}.
\]
Hence → (D).